Designing a Steel Spring: Calculations, Parameters, and Stability
Explore the intricate process of designing a steel spring to support a 200-pound load, including calculations for stress, spring constant, deflection, and stability. Learn about factors like buckling, Bergstresser factor, and spring index formula.
Video Summary
The design of a steel spring to support a 200-pound load with nine total coils, squared and ground ends, a wire diameter of 0.15 inches, an outer coil diameter of one inch, and a free length of six inches is a meticulous process. The focus lies on determining stress, spring constant, deflection, and stability of the spring, considering factors like buckling and parameters for unconditional stability. Calculations involve torsional and direct shear stress, a Bergstresser factor, and a spring index formula using mean coil diameter.
The design process for a spring entails adjusting parameters like coil diameter, wire diameter, and end configurations to achieve desired characteristics. The calculation of the Bergstresser factor, shearing stress in a spring, and the spring constant are crucial steps. The Bergstresser factor, found to be 1.254, leads to a shearing stress of 160.877 ksi. The spring constant is determined using an energy method and is found to be D^4 * G / 8 * D^3, where D is the mean coil diameter and G is the modulus of rigidity.
The spring, consisting of nine coils with a wire diameter of 0.1 inch and squared and ground ends, highlights the importance of different types of spring ends on force distribution. Calculating the number of active coils for a squared and ground end spring is essential. Determining the deflection of a spring under a specific load using Hooke's law and understanding fractional overrun - closure are key aspects of spring design. The calculation of the solid length of a spring and its implications on preventing the spring from going solid are also discussed.
The critical amount of deflection a spring can withstand before buckling under load is a critical consideration. The equation for critical deflection, taking into account parameters like slenderness ratio and elastic constants, determines the spring's buckling potential. Overloading the spring could lead to buckling, emphasizing the need for spring stability to prevent hazards.
Determining the absolute stability of a spring involves calculating the critical buckling force and minimum outer diameter required. The equation 1012 ensures the spring remains unconditionally stable. By considering the free length, mean coil diameter, and end condition constant alpha, the spring can be designed to prevent buckling. Adjusting the wire diameter to maintain the spring constant, determining the new fractional overrun, spring index, and maximum stress in the updated spring are vital steps. The results show a decrease in stress with the updated design, ensuring the spring's reliability.
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Keypoints
00:00:00
Introduction to Springs
Springs are a favorite topic for the speaker as they provide a foundation for discussing design in engineering. Design involves making choices about parameters for devices. The speaker plans to cover the design of Springs in detail in the next session.
00:01:00
Specifications of the Steel Spring
The problem involves supporting a 200-pound load using a steel spring with nine coils. The spring has squared and ground ends, a wire diameter of 0.15 inches, an outer coil diameter of one inch, and a free length of six inches. The focus is on determining stress, spring constant, and deflection.
00:02:10
Stability and Buckling of Springs
Springs can buckle, leading to instability. The speaker discusses the stability of the spring, including parameters for achieving unconditional stability. Factors like fractional overrun-closure and spring index are also considered to ensure stability.
00:03:54
Complexity of Spring Design
Designing a spring involves numerous interdependent constraints such as coil count, wire diameter, coil diameter, and end configurations. Springs may need to fit in holes or around rods, adding to the complexity of design tasks.
00:04:41
Calculating Maximum Stress in the Spring
To determine the maximum stress in the spring carrying a 200-pound load, reference is made to Chapter 10, specifically page 511, which discusses stress in the wire of a spring.
00:05:19
Torsional Stress in Springs
When squishing a spring downward, it changes the pitch of the spring, which is the number of coils per inch or the length per coil. This action twists the wire composing the spring, generating the largest component of stress in the spring element.
00:05:54
Direct Shear in Springs
Apart from torsional stress, direct shear is induced in springs. This shear arises from the reaction forces at a cut in the spring, transmitting linear loads between different parts of the spring.
00:07:00
Additional Stress Effects
In addition to torsional and direct shear stresses, there is a curvature effect in curved springs. This effect creates a non-uniform stress distribution, necessitating the use of a Bergstresser factor to adjust stress calculations.
00:08:01
Calculating Bergstresser Factor
To calculate the Bergstresser factor, one must first determine the spring index, which is the coil diameter divided by the wire diameter. The coil diameter refers to the mean coil diameter, obtained by subtracting the wire diameter from the outer coil diameter.
00:10:50
Calculation of Spring Index
The wire diameter mentioned is 0.46. The calculated spring index is 5.667, which is a unitless quantity. The actual wound up diameter is 0.85, denoted as D, and the spring index is denoted as capital C. The spring index is crucial for determining the Bergstresser factor.
00:12:19
Bergstresser Factor Calculation
The Bergstresser factor, denoted as K sub B, is calculated as 1.254 using the formula 4*(spring index) + 2 / 4*(spring index) - 3. This factor is essential for determining the shearing stress induced in the spring.
00:14:16
Shearing Stress Calculation
The shearing stress, denoted as tau, is calculated using the Bergstresser factor (1.254), force (200 pounds), mean coil diameter (0.85 inches), and wire diameter (0.15 inches). The resulting shearing stress is 160.877 ksi.
00:17:23
Analysis of Shearing Stress
The calculated shearing stress of 160.877 ksi may seem high, but it is within an acceptable range for spring materials made of high-strength steels. Typically, a maximum shear stress of 130-150 ksi is considered safe.
00:17:36
Finding Spring Constant and Deflection
The next step involves finding the spring constant and the deflection of the spring under the given load. A detailed derivation using an energy method on page 512 provides insights into determining these crucial parameters.
00:18:33
Spring Constant Equation
The spring constant equation, as per equation ten nine, states that the spring constant is equal to the wire diameter to the fourth power (0.15 inches to the fourth power) multiplied by the modulus of rigidity, denoted as G.
00:19:27
Modulus of Rigidity Value
For steel material, the modulus of rigidity value can be found in table ten fifteen, which specifies carbon steel as having a value of eleven point five million pounds per square inch (11.5 M psi).
00:20:01
Variable Material Properties
In the upcoming discussions, both the strength and elastic modulus values of materials will become variable, no longer remaining constant as they are currently assumed to be.
00:20:20
Compression Spring Design
In the design of compression springs, the end preparations play a crucial role. Options like plain ends, squared ends, or closed ends impact the distribution of forces and moments on the spring, influencing its stability and performance.
00:24:15
Different Ways to Modify Spring Ends
There are different ways to modify spring ends to distribute force more evenly. One method involves changing the pitch of the last coil to increase contact area. Another method is to grind the last coil to achieve a similar effect. The most effective approach is to use squared and ground ends, which combines changing the pitch and grinding the end to maximize contact area and balance the force distribution.
00:25:57
Importance of Prepared Spring Ends
Having prepared ends on a spring, such as squared and ground ends, is crucial for its effectiveness. Improperly cutting or modifying spring ends can reduce its efficiency. Prepared ends ensure optimal contact area and force distribution, enhancing the spring's performance.
00:26:16
Active Coils Calculation for Squared and Ground Ends
For squared and ground ends, the total number of coils is equal to the number of active coils plus two. By subtracting two from the total number of coils, the active coils for squared and ground ends can be determined. This calculation method provides a value for active coils that optimizes the spring's functionality.
00:29:08
Spring Constant Calculation
The spring constant is calculated to be 169.285 pounds per inch. This value represents the stiffness of the spring and is crucial for determining its deflection under different loads.
00:29:36
Deflection Calculation Using Hooke's Law
The deflection of the spring under a 200-pound load is calculated using Hooke's Law formula, which states that deflection (Delta) equals force (F) divided by the spring constant (K). The deflection is found to be 1.181 inches.
00:30:14
Understanding Fractional Overrun-Closure
Fractional overrun-closure is a parameter used to analyze the behavior of a spring. It involves calculating the difference between the spring's free length and its solid height. This metric provides insights into the spring's compression characteristics and is essential for designing and evaluating its performance.
00:30:53
Introduction to Fractional Overrun Closure
The speaker introduces the concept of fractional overrun closure, which is a valuable tool for optimized spring design. They mention a video game reference to Qbert, explaining how the Greek letter I reminds them of a snake bouncing on a pyramid.
00:31:35
Equation for Fractional Overrun Closure
The speaker discusses the equation for fractional overrun closure, which is implicitly defined in equation 1017. They explain that FS represents the force a spring carries when it goes solid, with FMax being the required force, such as 200 pounds in their example.
00:33:23
Calculating Solid Length of the Spring
The speaker explains how to calculate the solid length of the spring, which is crucial for determining the fractional overrun closure. They mention that the solid length (Ls) is calculated as the wire diameter multiplied by the total number of coils, providing a detailed example with specific values.
00:35:21
Deflection Calculation for Solid Spring
The speaker elaborates on calculating the deflection when the spring goes solid. They mention the free length of the spring, the solid length, and how to determine the deflection. Specific calculations are provided to illustrate the process.
00:37:53
Determining Fractional Overrun Closure
The speaker demonstrates how to determine the fractional overrun closure using the calculated force when the spring goes solid. They show the equation involving the maximum force and the force at solid state, providing a detailed example with specific numerical values.
00:38:32
Introduction to Fractional Over-Under Closure Parameter
The fractional over-under closure parameter, as defined on page 520, is expected to be greater than or equal to 0.15. This parameter indicates that there is approximately 15% more compression available before the spring reaches a solid state. Additionally, the guidelines mention that the number of active coils is typically between 3 and 15, and the spring index should fall between 4 and 12.
00:40:23
Discussion on Spring Buckling Under Load
The question of whether a spring will buckle under an applied load is crucial, especially for unsupported springs. Methods to prevent buckling include inserting a rod through the spring or placing it in a hole for support. Understanding the potential for buckling is essential to prevent failure in applications where springs are exposed and susceptible to buckling.
00:42:19
Equation for Critical Deflection Before Buckling
Equation 1010, denoted as Delta sub C R, represents the critical deflection at which a spring may buckle. It is calculated as the free length of the spring multiplied by a parameter c1 prime, adjusted by the effective slenderness ratio lambda e FF. This equation provides insight into the amount of deflection a spring can undergo before buckling occurs.
00:44:02
Introduction to Slenderness Ratio Calculation
The speaker introduces the concept of the slenderness ratio, denoted as L sub 0, which represents the free length of a spring. The free length mentioned is six inches. Additionally, the speaker mentions the unknown parameters C1 prime and C2 prime that affect the slenderness ratio calculation.
00:44:21
Calculation of Slenderness Ratio
To calculate the slenderness ratio, the speaker explains the formula involving the parameter alpha, which is multiplied by the free length divided by the mean coil diameter of the spring. Alpha accounts for various end conditions on springs and is crucial for determining the slenderness ratio.
00:45:06
End Condition Constants for Helical Compression Springs
The speaker discusses different end conditions for helical compression springs, such as springs supported between flat parallel surfaces, one end supported by a flat surface perpendicular to the spring axis, and the other end pivoted. These end conditions impact the value of alpha and subsequently affect the spring's behavior.
00:47:49
Effect of End Conditions on Slenderness of Springs
The speaker explains how different end conditions, such as having one end clamped and the other end free, or having no support for the spring, can influence the slenderness of a spring. Less support for the end of a spring can contribute to a higher slenderness effect.
00:48:09
Calculation of Slenderness Ratio Example
An example calculation is provided where the free length of six inches and the mean coil diameter of 0.85 inches are used to calculate the slenderness ratio, resulting in a value of 3.529. This calculation demonstrates the practical application of the slenderness ratio formula.
00:48:27
Dimensionless Elastic Constants C1 Prime and C2 Prime
The speaker mentions two dimensionless elastic constants, C1 Prime and C2 Prime, which are described as dimensionless elastic constants without specific names or equation numbers. These constants are calculated using the formula E/2 times E minus G and 2 pi squared times E minus G over 2G plus E, respectively.
00:50:44
Calculation of Buckling Prediction
By plugging in the values into the equation, the calculated value for the spring is 6.89, and the deflection is predicted to be 1.613 inches.
00:51:41
Analysis of Buckling Prediction
Comparing the predicted deflection of 1.613 inches to the actual deflection of 1.181 inches, it is concluded that the spring is not expected to buckle under the applied load.
00:52:52
Consideration of Overloading
There is a concern about overloading the spring, as exceeding the predicted deflection may lead to buckling. It is crucial to ensure the spring's stability under any circumstances.
00:53:28
Achieving Unconditional Stability
Equation 1012 provides a method to calculate if a spring will buckle under any circumstances. If the condition is met, the spring will be unconditionally stable.
00:54:40
Determining Critical Buckling Force
To find the load that would make the spring buckle, Hookes law is applied. The critical buckling force is calculated to be approximately 273 pounds.
00:57:57
Ensuring Absolute Stability
To achieve absolute stability, the minimum outer diameter needed for the spring is calculated to be 1.143 inches. Increasing the diameter would ensure the spring never buckles throughout its entire range.
00:58:45
Calculating New Wire Diameter
To calculate the new wire diameter, the spring constant of 169.285 pounds per inch is maintained. Using the equation G/8 * D^4, with a mean coil diameter of 1.143 inches and 7 coils, the new wire diameter is found to be 0.1873 inches, resulting in a new outer diameter of 1.33 inches.
01:01:53
Finding New Fractional Overrun, Spring Index, and Maximum Stress
With the updated wire and outer diameters, the new fractional overrun is 2.652, the new spring index is 6.10, the Newburgh stress factor is 1.234, and the shearing stress is 109.28 ksi. The solid length is 1.686 inches, leading to a deflection of 4.314 inches and a force of 730.35 pounds.
01:04:56
Effect of Changes on Stress Levels
By adjusting the wire diameter, the stress in the spring was reduced to 109.28 ksi, showing a slight decrease in stress levels. This adjustment resulted in a lower amount of shearing stress, indicating an improvement in the spring's performance.